👉CALCULATION OF REINFORCEMENT QUANTITY
Foundation: 15 m × 8 m
Perimeter: 2(15 + 8) = 46 m
Main bars: 4
Stirrup size: 15 × 15 cm
Stirrup spacing: 15 cm
Hook length: 7.5 cm each
🔹 1. Longitudinal Bars (Main Steel)
Total length: 46 × 4 = 184 m
12 m bars required: 184 ÷ 12 ≈ 16 bars
With 10% wastage: 18 bars
🔹 2. Stirrups (Ties)
Number: 46 ÷ 0.15 ≈ 307 stirrups
Length per stirrup: approximately 0.70 m
Total length: 307 × 0.70 = 214.9 m
12 m bars required: approximately 18 bars
📌 Note: These are preliminary estimates. Actual quantities depend on cover, bending details, lap lengths, and project specifications.
@ETCONP
Foundation: 15 m × 8 m
Perimeter: 2(15 + 8) = 46 m
Main bars: 4
Stirrup size: 15 × 15 cm
Stirrup spacing: 15 cm
Hook length: 7.5 cm each
🔹 1. Longitudinal Bars (Main Steel)
Total length: 46 × 4 = 184 m
12 m bars required: 184 ÷ 12 ≈ 16 bars
With 10% wastage: 18 bars
🔹 2. Stirrups (Ties)
Number: 46 ÷ 0.15 ≈ 307 stirrups
Length per stirrup: approximately 0.70 m
Total length: 307 × 0.70 = 214.9 m
12 m bars required: approximately 18 bars
📌 Note: These are preliminary estimates. Actual quantities depend on cover, bending details, lap lengths, and project specifications.
@ETCONP
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