Sardor Bazarbaev
Sizga navbatdagi #insta_savol ni taqdim etamiz.

Dastlabki 3 ta toสปgสปri javob egasiga @kuntesti mobil ilovamiz uchun 50 ta tanga beriladi.

Bu hali hammasi emas, eng noodatiy yechim egasiga mobil ilovamiz uchun 100 tanga beriladi. Instagramdagi video ostidagi izohlarda kutamiz:)

๐Ÿ“ฑ Bu safargi savolni koสปrish uchun: https://bit.ly/3fjPzbt

53 comments

Show 23 more comments
Firdavs Jo'rayev
12
O'lmasoy Sultonova
Tenglama 4ta natural yechimga ega:(1,3,8) , (5,5,2) , (7,1,4) ,(9,2,1) Ushbu tenglama x toq son bo'lganda yechimga ega,bunda x o'rniga 1,3,5,7,9ni qo'yib ishlaymiz,x=3da yechim yo'q, qolgan hollarda yechim mavjud.
O'lmasoy Sultonova
X+y+z=12
Muyassar
31*4,2+28*4,1+30*4=365
4,2+4,1+4=12,3
.
7+1+5=12 bir yildagi oylar soni
,,,,,
Gโ€˜oliblar aniqlandimi?
1
Bobur
31x+28y+30z=365. 28x+28y+28z+3x+2z=365. 28(x+y+z)+3x+2z=28โ€ข12+29. x+y+z=12 3x+2z=29 x=5. z=7. y=0 x=7 z=4 y=1 x=3 z=10 y= -1 tanlash usuli
OสปRINBOEV SARDOR QUDRAT oสปgสปli
7 ta oy 31 kundan iborat
4 ta oy 30 kundan iborat
7ร—31+1ร—28+4ร—30=365
1ta oy 28kundan iborat
4
เฎแƒฆโŽ  1.โ“จโ“คโ“ขโ“คโ“•_โ“žโ“šโ“”โ“ โŽแƒฆเฎ
31kun 28kun fevral oyi 30kun biroydagi kun
ๅฝก ๐€๐ก๐ฆ๐ž๐๐จ๐ฏ ๐’๐ก๐š๐ฆ๐ฌ๐ข๐๐๐ข๐ง๐ค๐ก๐š๐ง ๅฝก
x=7, y=1 va z=4
Zulxumor G'ulomova
365=1yil 7ta oy 31kun 4ta oy 30 kun 1ta oy 28 kun
Odiljonโœˆ๏ธ
X+y+z=12
1
sadoqat kudasheva
x+y+z=12
1
5229 admin
X=1,y=2,z=3
ะ—ะธัะดะฐ
Yanvar, fevral, mart
๐˜ผ๐™จ๐™ž๐™ก๐™—๐™š๐™  ๐˜ฝ๐™–๐™ญ๐™ง๐™–๐™ฃ๐™ค๐™ซ
12
1
MGM
 28ร—1+30ร—4+31ร—7=365 chunki 1ta oy 28 kundan iborat 4ta oy 30 kundan iborat 7ta oy esa 31 kundan iborat va javob :1+4+7=12
Ra'no Abdulxakova
7+1+4=12
Ra'no Abdulxakova
31ร—7+28ร—1+30ร—4=365
Gulyuz Olimjonovna
324
Maftuna.
324
Show next 9 comments